Base | Representation |
---|---|
bin | 111111000010101100011… |
… | …011111110101101000001 |
3 | 120100011012212022212110101 |
4 | 333002230123332231001 |
5 | 1031434341313101431 |
6 | 13114105554402401 |
7 | 624664310562136 |
oct | 77025433765501 |
9 | 16304185285411 |
10 | 4332220050241 |
11 | 1420314306566 |
12 | 59b743890401 |
13 | 2556acc21015 |
14 | 10d9756a658d |
15 | 77a57120961 |
hex | 3f0ac6feb41 |
4332220050241 has 2 divisors, whose sum is σ = 4332220050242. Its totient is φ = 4332220050240.
The previous prime is 4332220050227. The next prime is 4332220050259. The reversal of 4332220050241 is 1420500222334.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4157027576641 + 175192473600 = 2038879^2 + 418560^2 .
It is a cyclic number.
It is not a de Polignac number, because 4332220050241 - 231 = 4330072566593 is a prime.
It is not a weakly prime, because it can be changed into another prime (4332220050941) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2166110025120 + 2166110025121.
It is an arithmetic number, because the mean of its divisors is an integer number (2166110025121).
Almost surely, 24332220050241 is an apocalyptic number.
It is an amenable number.
4332220050241 is a deficient number, since it is larger than the sum of its proper divisors (1).
4332220050241 is an equidigital number, since it uses as much as digits as its factorization.
4332220050241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11520, while the sum is 28.
Adding to 4332220050241 its reverse (1420500222334), we get a palindrome (5752720272575).
The spelling of 4332220050241 in words is "four trillion, three hundred thirty-two billion, two hundred twenty million, fifty thousand, two hundred forty-one".
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