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4332254005393 is a prime number
BaseRepresentation
bin111111000010101110011…
…101100000100010010001
3120100011022020012222011121
4333002232131200202101
51031434424011133033
613114113210242241
7624665202312556
oct77025635404221
916304266188147
104332254005393
111420331498576
1259b753126381
132556b6c7c322
1410d979dc4a2d
1577a5a0cb62d
hex3f0ae760891

4332254005393 has 2 divisors, whose sum is σ = 4332254005394. Its totient is φ = 4332254005392.

The previous prime is 4332254005369. The next prime is 4332254005451. The reversal of 4332254005393 is 3935004522334.

4332254005393 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3337223815249 + 995030190144 = 1826807^2 + 997512^2 .

It is a cyclic number.

It is not a de Polignac number, because 4332254005393 - 217 = 4332253874321 is a prime.

It is not a weakly prime, because it can be changed into another prime (4332254005693) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2166127002696 + 2166127002697.

It is an arithmetic number, because the mean of its divisors is an integer number (2166127002697).

Almost surely, 24332254005393 is an apocalyptic number.

It is an amenable number.

4332254005393 is a deficient number, since it is larger than the sum of its proper divisors (1).

4332254005393 is an equidigital number, since it uses as much as digits as its factorization.

4332254005393 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1166400, while the sum is 43.

The spelling of 4332254005393 in words is "four trillion, three hundred thirty-two billion, two hundred fifty-four million, five thousand, three hundred ninety-three".