Base | Representation |
---|---|
bin | 101000010110100110… |
… | …110101000111011001 |
3 | 11010211200001202102112 |
4 | 220112212311013121 |
5 | 1202214202410440 |
6 | 31523253442105 |
7 | 3062506001363 |
oct | 502646650731 |
9 | 133750052375 |
10 | 43328950745 |
11 | 17415077003 |
12 | 8492940335 |
13 | 41169600c2 |
14 | 2150761d33 |
15 | 11d8da7965 |
hex | a169b51d9 |
43328950745 has 16 divisors (see below), whose sum is σ = 52248844800. Its totient is φ = 34493906304.
The previous prime is 43328950741. The next prime is 43328950771. The reversal of 43328950745 is 54705982334.
43328950745 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 43328950745 - 22 = 43328950741 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 43328950693 and 43328950702.
It is not an unprimeable number, because it can be changed into a prime (43328950741) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2714909 + ... + 2730821.
It is an arithmetic number, because the mean of its divisors is an integer number (3265552800).
Almost surely, 243328950745 is an apocalyptic number.
It is an amenable number.
43328950745 is a deficient number, since it is larger than the sum of its proper divisors (8919894055).
43328950745 is a wasteful number, since it uses less digits than its factorization.
43328950745 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18544.
The product of its (nonzero) digits is 3628800, while the sum is 50.
The spelling of 43328950745 in words is "forty-three billion, three hundred twenty-eight million, nine hundred fifty thousand, seven hundred forty-five".
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