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43331449241 is a prime number
BaseRepresentation
bin101000010110110000…
…010111000110011001
311010211211202200201102
4220112300113012121
51202220322333431
631523423201145
73062536145543
oct502660270631
9133754680642
1043331449241
1117416523183
1284937461b5
1341173263c2
142150c12693
1511d91ecdcb
hexa16c17199

43331449241 has 2 divisors, whose sum is σ = 43331449242. Its totient is φ = 43331449240.

The previous prime is 43331449211. The next prime is 43331449261. The reversal of 43331449241 is 14294413334.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 28932649216 + 14398800025 = 170096^2 + 119995^2 .

It is a cyclic number.

It is not a de Polignac number, because 43331449241 - 26 = 43331449177 is a prime.

It is a super-2 number, since 2×433314492412 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 43331449195 and 43331449204.

It is not a weakly prime, because it can be changed into another prime (43331449201) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21665724620 + 21665724621.

It is an arithmetic number, because the mean of its divisors is an integer number (21665724621).

Almost surely, 243331449241 is an apocalyptic number.

It is an amenable number.

43331449241 is a deficient number, since it is larger than the sum of its proper divisors (1).

43331449241 is an equidigital number, since it uses as much as digits as its factorization.

43331449241 is an evil number, because the sum of its binary digits is even.

The product of its digits is 124416, while the sum is 38.

The spelling of 43331449241 in words is "forty-three billion, three hundred thirty-one million, four hundred forty-nine thousand, two hundred forty-one".