Base | Representation |
---|---|
bin | 111111000011101000111… |
… | …001001100100011100001 |
3 | 120100020211112220020100000 |
4 | 333003220321030203201 |
5 | 1031443430442421423 |
6 | 13114354350250213 |
7 | 625031405116245 |
oct | 77035071144341 |
9 | 16306745806300 |
10 | 4333234342113 |
11 | 1420794901006 |
12 | 59b9874b6969 |
13 | 2558120c3421 |
14 | 10da30294425 |
15 | 77ab61c6843 |
hex | 3f0e8e4c8e1 |
4333234342113 has 12 divisors (see below), whose sum is σ = 6490935393488. Its totient is φ = 2888822894580.
The previous prime is 4333234342109. The next prime is 4333234342133. The reversal of 4333234342113 is 3112434323334.
4333234342113 is a `hidden beast` number, since 4 + 3 + 3 + 3 + 2 + 3 + 434 + 211 + 3 = 666.
4333234342113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 4333234342113 - 22 = 4333234342109 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4333234342103) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 8916119803 + ... + 8916120288.
Almost surely, 24333234342113 is an apocalyptic number.
It is an amenable number.
4333234342113 is a deficient number, since it is larger than the sum of its proper divisors (2157701051375).
4333234342113 is an equidigital number, since it uses as much as digits as its factorization.
4333234342113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17832240106 (or 17832240094 counting only the distinct ones).
The product of its digits is 186624, while the sum is 36.
Adding to 4333234342113 its reverse (3112434323334), we get a palindrome (7445668665447).
The spelling of 4333234342113 in words is "four trillion, three hundred thirty-three billion, two hundred thirty-four million, three hundred forty-two thousand, one hundred thirteen".
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