Base | Representation |
---|---|
bin | 111111000011110101010… |
… | …010111101110101001011 |
3 | 120100021101001102220012201 |
4 | 333003311102331311023 |
5 | 1031444342230033024 |
6 | 13114431142221031 |
7 | 625036512564343 |
oct | 77036522756513 |
9 | 16307331386181 |
10 | 4333442424139 |
11 | 1420891304124 |
12 | 59ba25124777 |
13 | 25584624a29a |
14 | 10da4db7bd23 |
15 | 77ac95ca744 |
hex | 3f0f54bdd4b |
4333442424139 has 2 divisors, whose sum is σ = 4333442424140. Its totient is φ = 4333442424138.
The previous prime is 4333442424041. The next prime is 4333442424169. The reversal of 4333442424139 is 9314242443334.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4333442424139 - 211 = 4333442422091 is a prime.
It is not a weakly prime, because it can be changed into another prime (4333442424169) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2166721212069 + 2166721212070.
It is an arithmetic number, because the mean of its divisors is an integer number (2166721212070).
Almost surely, 24333442424139 is an apocalyptic number.
4333442424139 is a deficient number, since it is larger than the sum of its proper divisors (1).
4333442424139 is an equidigital number, since it uses as much as digits as its factorization.
4333442424139 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2985984, while the sum is 46.
The spelling of 4333442424139 in words is "four trillion, three hundred thirty-three billion, four hundred forty-two million, four hundred twenty-four thousand, one hundred thirty-nine".
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