Search a number
-
+
433400240113 = 538356197861
BaseRepresentation
bin1100100111010001010…
…10101101011111110001
31112102200102000100220221
412103220222231133301
524100100430140423
6531033515133041
743212030154231
oct6235052553761
91472612010827
10433400240113
11157893156125
126bbb4a44181
1331b3c2b1629
1416d9603bcc1
15b418cc5e5d
hex64e8aad7f1

433400240113 has 8 divisors (see below), whose sum is σ = 441587399976. Its totient is φ = 425213443200.

The previous prime is 433400240081. The next prime is 433400240137. The reversal of 433400240113 is 311042004334.

It can be written as a sum of positive squares in 4 ways, for example, as 105978244849 + 327421995264 = 325543^2 + 572208^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 433400240113 - 25 = 433400240081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (433400240213) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4379803 + ... + 4477663.

It is an arithmetic number, because the mean of its divisors is an integer number (55198424997).

Almost surely, 2433400240113 is an apocalyptic number.

It is an amenable number.

433400240113 is a deficient number, since it is larger than the sum of its proper divisors (8187159863).

433400240113 is an equidigital number, since it uses as much as digits as its factorization.

433400240113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 181475.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 433400240113 its reverse (311042004334), we get a palindrome (744442244447).

The spelling of 433400240113 in words is "four hundred thirty-three billion, four hundred million, two hundred forty thousand, one hundred thirteen".

Divisors: 1 53 83561 97861 4428733 5186633 8177363021 433400240113