Base | Representation |
---|---|
bin | 101000011000101100… |
… | …111101011010110001 |
3 | 11010221010020010200001 |
4 | 220120230331122301 |
5 | 1202302203041144 |
6 | 31530551230001 |
7 | 3063413604436 |
oct | 503054753261 |
9 | 133833203601 |
10 | 43364112049 |
11 | 17432a02235 |
12 | 84a2678301 |
13 | 41210213cb |
14 | 21552b5b8d |
15 | 11dc000bd4 |
hex | a18b3d6b1 |
43364112049 has 2 divisors, whose sum is σ = 43364112050. Its totient is φ = 43364112048.
The previous prime is 43364112017. The next prime is 43364112079. The reversal of 43364112049 is 94021146334.
43364112049 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 38359964449 + 5004147600 = 195857^2 + 70740^2 .
It is a cyclic number.
It is not a de Polignac number, because 43364112049 - 25 = 43364112017 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 43364111999 and 43364112017.
It is not a weakly prime, because it can be changed into another prime (43364112079) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21682056024 + 21682056025.
It is an arithmetic number, because the mean of its divisors is an integer number (21682056025).
Almost surely, 243364112049 is an apocalyptic number.
It is an amenable number.
43364112049 is a deficient number, since it is larger than the sum of its proper divisors (1).
43364112049 is an equidigital number, since it uses as much as digits as its factorization.
43364112049 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 62208, while the sum is 37.
The spelling of 43364112049 in words is "forty-three billion, three hundred sixty-four million, one hundred twelve thousand, forty-nine".
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