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434001320034 = 23211359954911
BaseRepresentation
bin1100101000011000111…
…11101001100001100010
31112111020022001101120020
412110030133221201202
524102313314220114
6531213310254310
743232646231642
oct6241437514142
91474208041506
10434001320034
11158071481397
12701421b7396
1331c06997919
1417011bc6522
15b451958aa9
hex650c7e9862

434001320034 has 32 divisors (see below), whose sum is σ = 874546606080. Its totient is φ = 143580267600.

The previous prime is 434001320029. The next prime is 434001320101. The reversal of 434001320034 is 430023100434.

It is a super-3 number, since 3×4340013200343 (a number of 36 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 434001319986 and 434001320013.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 22962 + ... + 931949.

It is an arithmetic number, because the mean of its divisors is an integer number (27329581440).

Almost surely, 2434001320034 is an apocalyptic number.

434001320034 is an abundant number, since it is smaller than the sum of its proper divisors (440545286046).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

434001320034 is a wasteful number, since it uses less digits than its factorization.

434001320034 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 955486.

The product of its (nonzero) digits is 3456, while the sum is 24.

Adding to 434001320034 its reverse (430023100434), we get a palindrome (864024420468).

The spelling of 434001320034 in words is "four hundred thirty-four billion, one million, three hundred twenty thousand, thirty-four".

Divisors: 1 2 3 6 211 359 422 633 718 1077 1266 2154 75749 151498 227247 454494 954911 1909822 2864733 5729466 201486221 342813049 402972442 604458663 685626098 1028439147 1208917326 2056878294 72333553339 144667106678 217000660017 434001320034