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434002144219993 is a prime number
BaseRepresentation
bin110001010101110001111111…
…1101000110101001101011001
32002220200012101122101020102101
41202223203333220311031121
5423341142342410014433
64135013455502203401
7160262422502034136
oct14253437750651531
92086605348336371
10434002144219993
11116317303aaa558
1240814633b83561
13158222c3a86b4b
147925b5ca1158d
1535295d226207d
hex18ab8ffa35359

434002144219993 has 2 divisors, whose sum is σ = 434002144219994. Its totient is φ = 434002144219992.

The previous prime is 434002144219961. The next prime is 434002144220039. The reversal of 434002144219993 is 399912441200434.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 422788935196224 + 11213209023769 = 20561832^2 + 3348613^2 .

It is a cyclic number.

It is not a de Polignac number, because 434002144219993 - 25 = 434002144219961 is a prime.

It is a super-2 number, since 2×4340021442199932 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (434002144219933) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 217001072109996 + 217001072109997.

It is an arithmetic number, because the mean of its divisors is an integer number (217001072109997).

Almost surely, 2434002144219993 is an apocalyptic number.

It is an amenable number.

434002144219993 is a deficient number, since it is larger than the sum of its proper divisors (1).

434002144219993 is an equidigital number, since it uses as much as digits as its factorization.

434002144219993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6718464, while the sum is 55.

The spelling of 434002144219993 in words is "four hundred thirty-four trillion, two billion, one hundred forty-four million, two hundred nineteen thousand, nine hundred ninety-three".