434013310433 has 4 divisors (see below), whose sum is σ = 434044546068. Its totient is φ = 433982074800.

The previous prime is 434013310411. The next prime is 434013310453. The reversal of 434013310433 is 334013310434.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 211519967569 + 222493342864 = 459913^2 + 471692^2 .

It is a cyclic number.

It is not a de Polignac number, because 434013310433 - 2⁶ = 434013310369 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 434013310396 and 434013310405.

It is not an unprimeable number, because it can be changed into a prime (434013310453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15596966 + ... + 15624767.

It is an arithmetic number, because the mean of its divisors is an integer number (108511136517).

Almost surely, 2^434013310433 is an apocalyptic number.

It is an amenable number.

434013310433 is a deficient number, since it is larger than the sum of its proper divisors (31235635).

434013310433 is a wasteful number, since it uses less digits than its factorization.

434013310433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 31235634.

The product of its (nonzero) digits is 15552, while the sum is 29.

Adding to 434013310433 its reverse (334013310434), we get a palindrome (768026620867).

Subtracting from 434013310433 its reverse (334013310434), we obtain a palindrome (99999999999).

The spelling of 434013310433 in words is "four hundred thirty-four billion, thirteen million, three hundred ten thousand, four hundred thirty-three".