Base | Representation |
---|---|
bin | 111111001010001001110… |
… | …111101001001011000001 |
3 | 120100220220002112012122201 |
4 | 333022021313221023001 |
5 | 1032102242342042423 |
6 | 13121512452233201 |
7 | 625366642403611 |
oct | 77121167511301 |
9 | 16326802465581 |
10 | 4340230034113 |
11 | 1423754782a46 |
12 | 5a11ba30b801 |
13 | 25638854b54c |
14 | 1100d540ca41 |
15 | 77d7543e2ad |
hex | 3f289de92c1 |
4340230034113 has 8 divisors (see below), whose sum is σ = 4387785292800. Its totient is φ = 4292778950688.
The previous prime is 4340230034093. The next prime is 4340230034197. The reversal of 4340230034113 is 3114300320434.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4340230034113 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4340230134113) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 25960033 + ... + 26126686.
It is an arithmetic number, because the mean of its divisors is an integer number (548473161600).
Almost surely, 24340230034113 is an apocalyptic number.
It is an amenable number.
4340230034113 is a deficient number, since it is larger than the sum of its proper divisors (47555258687).
4340230034113 is a wasteful number, since it uses less digits than its factorization.
4340230034113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 52087631.
The product of its (nonzero) digits is 10368, while the sum is 28.
Adding to 4340230034113 its reverse (3114300320434), we get a palindrome (7454530354547).
The spelling of 4340230034113 in words is "four trillion, three hundred forty billion, two hundred thirty million, thirty-four thousand, one hundred thirteen".
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