Base | Representation |
---|---|
bin | 111111001010001010100… |
… | …010010010101111101001 |
3 | 120100220220212120020011221 |
4 | 333022022202102233221 |
5 | 1032102303222330231 |
6 | 13121513532022041 |
7 | 625400136420406 |
oct | 77121242225751 |
9 | 16326825506157 |
10 | 4340241214441 |
11 | 1423760019990 |
12 | 5a1202001921 |
13 | 25638a964422 |
14 | 1100d6abd2ad |
15 | 77d763ebd11 |
hex | 3f28a892be9 |
4340241214441 has 32 divisors (see below), whose sum is σ = 4914503884800. Its totient is φ = 3797350761600.
The previous prime is 4340241214423. The next prime is 4340241214469. The reversal of 4340241214441 is 1444121420434.
It is not a de Polignac number, because 4340241214441 - 211 = 4340241212393 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 4340241214397 and 4340241214406.
It is not an unprimeable number, because it can be changed into a prime (4340241212441) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 149478861 + ... + 149507893.
It is an arithmetic number, because the mean of its divisors is an integer number (153578246400).
Almost surely, 24340241214441 is an apocalyptic number.
It is an amenable number.
4340241214441 is a deficient number, since it is larger than the sum of its proper divisors (574262670359).
4340241214441 is a wasteful number, since it uses less digits than its factorization.
4340241214441 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 31477.
The product of its (nonzero) digits is 49152, while the sum is 34.
Adding to 4340241214441 its reverse (1444121420434), we get a palindrome (5784362634875).
The spelling of 4340241214441 in words is "four trillion, three hundred forty billion, two hundred forty-one million, two hundred fourteen thousand, four hundred forty-one".
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