Base | Representation |
---|---|
bin | 1100101000100101001… |
… | …01000110110101110011 |
3 | 1112111111102011022100002 |
4 | 12110102211012311303 |
5 | 24103020433223011 |
6 | 531231354420215 |
7 | 43235326065242 |
oct | 6242245066563 |
9 | 1474442138302 |
10 | 434103414131 |
11 | 158114073182 |
12 | 7017043166b |
13 | 31c21b9262a |
14 | 170215a0959 |
15 | b45a8c3c3b |
hex | 6512946d73 |
434103414131 has 2 divisors, whose sum is σ = 434103414132. Its totient is φ = 434103414130.
The previous prime is 434103414037. The next prime is 434103414137. The reversal of 434103414131 is 131414301434.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-434103414131 is a prime.
It is a super-2 number, since 2×4341034141312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 434103414094 and 434103414103.
It is not a weakly prime, because it can be changed into another prime (434103414137) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 217051707065 + 217051707066.
It is an arithmetic number, because the mean of its divisors is an integer number (217051707066).
Almost surely, 2434103414131 is an apocalyptic number.
434103414131 is a deficient number, since it is larger than the sum of its proper divisors (1).
434103414131 is an equidigital number, since it uses as much as digits as its factorization.
434103414131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 434103414131 its reverse (131414301434), we get a palindrome (565517715565).
The spelling of 434103414131 in words is "four hundred thirty-four billion, one hundred three million, four hundred fourteen thousand, one hundred thirty-one".
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