Base | Representation |
---|---|
bin | 111111001010111110011… |
… | …000101001001011100011 |
3 | 120101000011111102000000110 |
4 | 333022332120221023203 |
5 | 1032111043420201011 |
6 | 13122140124422403 |
7 | 625430531343321 |
oct | 77127630511343 |
9 | 16330144360013 |
10 | 4341111100131 |
11 | 1424067052983 |
12 | 5a14053a7a03 |
13 | 256498c45aa0 |
14 | 11017a43ad11 |
15 | 77dc797aba6 |
hex | 3f2be6292e3 |
4341111100131 has 32 divisors (see below), whose sum is σ = 6323275445760. Its totient is φ = 2632955673600.
The previous prime is 4341111100093. The next prime is 4341111100133. The reversal of 4341111100131 is 1310011111434.
It is not a de Polignac number, because 4341111100131 - 214 = 4341111083747 is a prime.
It is a super-2 number, since 2×43411111001312 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 4341111100098 and 4341111100107.
It is not an unprimeable number, because it can be changed into a prime (4341111100133) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 8162760 + ... + 8678298.
It is an arithmetic number, because the mean of its divisors is an integer number (197602357680).
Almost surely, 24341111100131 is an apocalyptic number.
4341111100131 is a deficient number, since it is larger than the sum of its proper divisors (1982164345629).
4341111100131 is a wasteful number, since it uses less digits than its factorization.
4341111100131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 518667.
The product of its (nonzero) digits is 144, while the sum is 21.
Adding to 4341111100131 its reverse (1310011111434), we get a palindrome (5651122211565).
The spelling of 4341111100131 in words is "four trillion, three hundred forty-one billion, one hundred eleven million, one hundred thousand, one hundred thirty-one".
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