4341123000121 has 2 divisors, whose sum is σ = 4341123000122. Its totient is φ = 4341123000120.

The previous prime is 4341123000101. The next prime is 4341123000217. The reversal of 4341123000121 is 1210003211434.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4324049919225 + 17073080896 = 2079435^2 + 130664^2 .

It is a cyclic number.

It is not a de Polignac number, because 4341123000121 - 2¹¹ = 4341122998073 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 4341123000092 and 4341123000101.

It is not a weakly prime, because it can be changed into another prime (4341123000101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2170561500060 + 2170561500061.

It is an arithmetic number, because the mean of its divisors is an integer number (2170561500061).

Almost surely, 2^{4341123000121} is an apocalyptic number.

It is an amenable number.

4341123000121 is a deficient number, since it is larger than the sum of its proper divisors (1).

4341123000121 is an equidigital number, since it uses as much as digits as its factorization.

4341123000121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 4341123000121 its reverse (1210003211434), we get a palindrome (5551126211555).

The spelling of 4341123000121 in words is "four trillion, three hundred forty-one billion, one hundred twenty-three million, one hundred twenty-one", and thus it is an aban number.