Base | Representation |
---|---|
bin | 111111001010111111100… |
… | …100101101110011110010 |
3 | 120101000012212221011011110 |
4 | 333022333210231303302 |
5 | 1032111114021321114 |
6 | 13122142120054150 |
7 | 625431163011063 |
oct | 77127744556362 |
9 | 16330185834143 |
10 | 4341131042034 |
11 | 1424077333596 |
12 | 5a1410004356 |
13 | 2564a0108927 |
14 | 11017cd4c56a |
15 | 77dc95b9759 |
hex | 3f2bf92dcf2 |
4341131042034 has 16 divisors (see below), whose sum is σ = 8682302649888. Its totient is φ = 1447036919712.
The previous prime is 4341131042011. The next prime is 4341131042069. The reversal of 4341131042034 is 4302401311434.
It is a super-2 number, since 2×43411310420342 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 4341131041992 and 4341131042010.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 197667 + ... + 2953190.
It is an arithmetic number, because the mean of its divisors is an integer number (542643915618).
Almost surely, 24341131042034 is an apocalyptic number.
4341131042034 is an abundant number, since it is smaller than the sum of its proper divisors (4341171607854).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
4341131042034 is a wasteful number, since it uses less digits than its factorization.
4341131042034 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3380489.
The product of its (nonzero) digits is 13824, while the sum is 30.
Adding to 4341131042034 its reverse (4302401311434), we get a palindrome (8643532353468).
The spelling of 4341131042034 in words is "four trillion, three hundred forty-one billion, one hundred thirty-one million, forty-two thousand, thirty-four".
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