434121434113 has 4 divisors (see below), whose sum is σ = 434453586480. Its totient is φ = 433789281748.

The previous prime is 434121434093. The next prime is 434121434119. The reversal of 434121434113 is 311434121434.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 434121434113 - 2¹⁷ = 434121303041 is a prime.

It is a super-2 number, since 2×434121434113² (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (434121434119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 166074223 + ... + 166076836.

It is an arithmetic number, because the mean of its divisors is an integer number (108613396620).

Almost surely, 2^434121434113 is an apocalyptic number.

It is an amenable number.

434121434113 is a deficient number, since it is larger than the sum of its proper divisors (332152367).

434121434113 is a wasteful number, since it uses less digits than its factorization.

434121434113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 332152366.

The product of its digits is 13824, while the sum is 31.

Adding to 434121434113 its reverse (311434121434), we get a palindrome (745555555547).

The spelling of 434121434113 in words is "four hundred thirty-four billion, one hundred twenty-one million, four hundred thirty-four thousand, one hundred thirteen".