Base | Representation |
---|---|
bin | 1100101000100111100… |
… | …00010010000111100001 |
3 | 1112111112210020112020121 |
4 | 12110103300102013201 |
5 | 24103041004333441 |
6 | 531233341040241 |
7 | 43235655434104 |
oct | 6242360220741 |
9 | 1474483215217 |
10 | 434123121121 |
11 | 158124203348 |
12 | 70176b56081 |
13 | 31c25ca2581 |
14 | 1702405073b |
15 | b45c4b7dd1 |
hex | 6513c121e1 |
434123121121 has 4 divisors (see below), whose sum is σ = 434124991744. Its totient is φ = 434121250500.
The previous prime is 434123121083. The next prime is 434123121127. The reversal of 434123121121 is 121121321434.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 121121321434 = 2 ⋅60560660717.
It is a cyclic number.
It is not a de Polignac number, because 434123121121 - 215 = 434123088353 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (434123121127) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 528105 + ... + 1071046.
It is an arithmetic number, because the mean of its divisors is an integer number (108531247936).
Almost surely, 2434123121121 is an apocalyptic number.
It is an amenable number.
434123121121 is a deficient number, since it is larger than the sum of its proper divisors (1870623).
434123121121 is a wasteful number, since it uses less digits than its factorization.
434123121121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1870622.
The product of its digits is 1152, while the sum is 25.
Adding to 434123121121 its reverse (121121321434), we get a palindrome (555244442555).
The spelling of 434123121121 in words is "four hundred thirty-four billion, one hundred twenty-three million, one hundred twenty-one thousand, one hundred twenty-one".
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