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4341322423401 = 31447107474467
BaseRepresentation
bin111111001011001010111…
…110110001110001101001
3120101000201020001100001020
4333023022332301301221
51032112012020022101
613122213114043053
7625436005511205
oct77131276616151
916330636040036
104341322423401
11142416536a207
125a1464119489
13256500966042
1411019a529b05
1577ddb2c0136
hex3f2cafb1c69

4341322423401 has 4 divisors (see below), whose sum is σ = 5788429897872. Its totient is φ = 2894214948932.

The previous prime is 4341322423393. The next prime is 4341322423453. The reversal of 4341322423401 is 1043242231434.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4341322423401 - 23 = 4341322423393 is a prime.

It is not an unprimeable number, because it can be changed into a prime (4341322443401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 723553737231 + ... + 723553737236.

It is an arithmetic number, because the mean of its divisors is an integer number (1447107474468).

Almost surely, 24341322423401 is an apocalyptic number.

It is an amenable number.

4341322423401 is a deficient number, since it is larger than the sum of its proper divisors (1447107474471).

4341322423401 is a wasteful number, since it uses less digits than its factorization.

4341322423401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1447107474470.

The product of its (nonzero) digits is 55296, while the sum is 33.

Adding to 4341322423401 its reverse (1043242231434), we get a palindrome (5384564654835).

The spelling of 4341322423401 in words is "four trillion, three hundred forty-one billion, three hundred twenty-two million, four hundred twenty-three thousand, four hundred one".

Divisors: 1 3 1447107474467 4341322423401