Base | Representation |
---|---|
bin | 10011101111011111111111… |
… | …00111111111101111100001 |
3 | 12200201021220001221010011012 |
4 | 21313233333213333233201 |
5 | 21142241343410313312 |
6 | 232155521443430305 |
7 | 12100344401001536 |
oct | 1167577747775741 |
9 | 180637801833135 |
10 | 43413523135457 |
11 | 12918632026a52 |
12 | 4a519b9085395 |
13 | 1b2bb543000a7 |
14 | aa1323598d8d |
15 | 504443194322 |
hex | 277bff9ffbe1 |
43413523135457 has 2 divisors, whose sum is σ = 43413523135458. Its totient is φ = 43413523135456.
The previous prime is 43413523135399. The next prime is 43413523135513. The reversal of 43413523135457 is 75453132531434.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 36816145952161 + 6597377183296 = 6067631^2 + 2568536^2 .
It is a cyclic number.
It is not a de Polignac number, because 43413523135457 - 226 = 43413456026593 is a prime.
It is not a weakly prime, because it can be changed into another prime (43413523135057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21706761567728 + 21706761567729.
It is an arithmetic number, because the mean of its divisors is an integer number (21706761567729).
Almost surely, 243413523135457 is an apocalyptic number.
It is an amenable number.
43413523135457 is a deficient number, since it is larger than the sum of its proper divisors (1).
43413523135457 is an equidigital number, since it uses as much as digits as its factorization.
43413523135457 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 9072000, while the sum is 50.
The spelling of 43413523135457 in words is "forty-three trillion, four hundred thirteen billion, five hundred twenty-three million, one hundred thirty-five thousand, four hundred fifty-seven".
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