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43414113 = 314471371
BaseRepresentation
bin1010010110011…
…1001001100001
310000200122222010
42211213021201
542103222423
64150303133
71035004521
oct245471141
9100618863
1043414113
1122562736
1212657aa9
138cc0832
145aa1681
153c28693
hex2967261

43414113 has 4 divisors (see below), whose sum is σ = 57885488. Its totient is φ = 28942740.

The previous prime is 43414099. The next prime is 43414139. The reversal of 43414113 is 31141434.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 43414113 - 25 = 43414081 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 43414113.

It is not an unprimeable number, because it can be changed into a prime (43414013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7235683 + ... + 7235688.

It is an arithmetic number, because the mean of its divisors is an integer number (14471372).

Almost surely, 243414113 is an apocalyptic number.

It is an amenable number.

43414113 is a deficient number, since it is larger than the sum of its proper divisors (14471375).

43414113 is a wasteful number, since it uses less digits than its factorization.

43414113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14471374.

The product of its digits is 576, while the sum is 21.

The square root of 43414113 is about 6588.9386854030. The cubic root of 43414113 is about 351.4608681355.

Adding to 43414113 its reverse (31141434), we get a palindrome (74555547).

The spelling of 43414113 in words is "forty-three million, four hundred fourteen thousand, one hundred thirteen".

Divisors: 1 3 14471371 43414113