Base | Representation |
---|---|
bin | 111111001011010000011… |
… | …100111101000100001011 |
3 | 120101000221121210002100212 |
4 | 333023100130331010023 |
5 | 1032112204020020133 |
6 | 13122230153351335 |
7 | 625441201665665 |
oct | 77132034750413 |
9 | 16330847702325 |
10 | 4341414220043 |
11 | 14242021683aa |
12 | 5a148aa0854b |
13 | 256516996994 |
14 | 1101a87c3535 |
15 | 77de43a4148 |
hex | 3f2d073d10b |
4341414220043 has 2 divisors, whose sum is σ = 4341414220044. Its totient is φ = 4341414220042.
The previous prime is 4341414220027. The next prime is 4341414220081. The reversal of 4341414220043 is 3400224141434.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4341414220043 - 24 = 4341414220027 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4341414219991 and 4341414220009.
It is not a weakly prime, because it can be changed into another prime (4341414226043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2170707110021 + 2170707110022.
It is an arithmetic number, because the mean of its divisors is an integer number (2170707110022).
Almost surely, 24341414220043 is an apocalyptic number.
4341414220043 is a deficient number, since it is larger than the sum of its proper divisors (1).
4341414220043 is an equidigital number, since it uses as much as digits as its factorization.
4341414220043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36864, while the sum is 32.
Adding to 4341414220043 its reverse (3400224141434), we get a palindrome (7741638361477).
The spelling of 4341414220043 in words is "four trillion, three hundred forty-one billion, four hundred fourteen million, two hundred twenty thousand, forty-three".
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