Base | Representation |
---|---|
bin | 1100101000110010001… |
… | …00001101111110101011 |
3 | 1112111202222220212221102 |
4 | 12110121010031332223 |
5 | 24103231312430011 |
6 | 531250243032015 |
7 | 43241120040635 |
oct | 6243104157653 |
9 | 1474688825842 |
10 | 434212233131 |
11 | 15816a538536 |
12 | 701a096b60b |
13 | 31c3b5a3281 |
14 | 17031c09a55 |
15 | b46521b73b |
hex | 651910dfab |
434212233131 has 2 divisors, whose sum is σ = 434212233132. Its totient is φ = 434212233130.
The previous prime is 434212233101. The next prime is 434212233149. The reversal of 434212233131 is 131332212434.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-434212233131 is a prime.
It is a super-2 number, since 2×4342122331312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 434212233094 and 434212233103.
It is not a weakly prime, because it can be changed into another prime (434212233101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 217106116565 + 217106116566.
It is an arithmetic number, because the mean of its divisors is an integer number (217106116566).
Almost surely, 2434212233131 is an apocalyptic number.
434212233131 is a deficient number, since it is larger than the sum of its proper divisors (1).
434212233131 is an equidigital number, since it uses as much as digits as its factorization.
434212233131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 10368, while the sum is 29.
Adding to 434212233131 its reverse (131332212434), we get a palindrome (565544445565).
The spelling of 434212233131 in words is "four hundred thirty-four billion, two hundred twelve million, two hundred thirty-three thousand, one hundred thirty-one".
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