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43423130041 = 139544957331
BaseRepresentation
bin101000011100001110…
…000110000110111001
311011002020021120010121
4220130032012012321
51202412310130131
631540500213241
73065031341524
oct503416060671
9134066246117
1043423130041
1117463252335
1284ba39a221
1341303163b5
14215d079bbb
1511e22ac911
hexa1c3861b9

43423130041 has 8 divisors (see below), whose sum is σ = 43744316000. Its totient is φ = 43102069920.

The previous prime is 43423130029. The next prime is 43423130057. The reversal of 43423130041 is 14003132434.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 43423130041 - 27 = 43423129913 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 43423129988 and 43423130015.

It is not an unprimeable number, because it can be changed into a prime (43423130011) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 728746 + ... + 786076.

It is an arithmetic number, because the mean of its divisors is an integer number (5468039500).

Almost surely, 243423130041 is an apocalyptic number.

It is an amenable number.

43423130041 is a deficient number, since it is larger than the sum of its proper divisors (321185959).

43423130041 is a wasteful number, since it uses less digits than its factorization.

43423130041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 62919.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 43423130041 its reverse (14003132434), we get a palindrome (57426262475).

The spelling of 43423130041 in words is "forty-three billion, four hundred twenty-three million, one hundred thirty thousand, forty-one".

Divisors: 1 139 5449 57331 757411 7969009 312396619 43423130041