Base | Representation |
---|---|
bin | 10011101111110011100101… |
… | …00110110100010101010011 |
3 | 12200202022001011021222001111 |
4 | 21313321302212310111103 |
5 | 21142424414242003021 |
6 | 232204421330314151 |
7 | 12101166150035320 |
oct | 1167716246642523 |
9 | 180668034258044 |
10 | 43424042141011 |
11 | 1292203a7a9574 |
12 | 4a53a53a28957 |
13 | 1b2cb3c69822c |
14 | aa1a4061db47 |
15 | 50485b8c18e1 |
hex | 277e729b4553 |
43424042141011 has 4 divisors (see below), whose sum is σ = 49627476732592. Its totient is φ = 37220607549432.
The previous prime is 43424042140939. The next prime is 43424042141023. The reversal of 43424042141011 is 11014124042434.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 43424042141011 - 27 = 43424042140883 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (43424042141111) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3101717295780 + ... + 3101717295793.
It is an arithmetic number, because the mean of its divisors is an integer number (12406869183148).
Almost surely, 243424042141011 is an apocalyptic number.
43424042141011 is a deficient number, since it is larger than the sum of its proper divisors (6203434591581).
43424042141011 is an equidigital number, since it uses as much as digits as its factorization.
43424042141011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6203434591580.
The product of its (nonzero) digits is 12288, while the sum is 31.
Adding to 43424042141011 its reverse (11014124042434), we get a palindrome (54438166183445).
The spelling of 43424042141011 in words is "forty-three trillion, four hundred twenty-four billion, forty-two million, one hundred forty-one thousand, eleven".
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