Base | Representation |
---|---|
bin | 1100101000110111000… |
… | …01101111000000111011 |
3 | 1112111212212121201210210 |
4 | 12110123201233000323 |
5 | 24103322400300201 |
6 | 531254320042203 |
7 | 43242131026353 |
oct | 6243341570073 |
9 | 1474785551723 |
10 | 434253525051 |
11 | 158190880795 |
12 | 701b2763363 |
13 | 31c46cccb68 |
14 | 170374b7b63 |
15 | b468b761d6 |
hex | 651b86f03b |
434253525051 has 16 divisors (see below), whose sum is σ = 613082815488. Its totient is φ = 272464348800.
The previous prime is 434253524963. The next prime is 434253525071. The reversal of 434253525051 is 150525352434.
434253525051 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 434253525051 - 217 = 434253393979 is a prime.
It is a super-2 number, since 2×4342535250512 (a number of 24 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (434253525071) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1803886 + ... + 2030396.
It is an arithmetic number, because the mean of its divisors is an integer number (38317675968).
Almost surely, 2434253525051 is an apocalyptic number.
434253525051 is a deficient number, since it is larger than the sum of its proper divisors (178829290437).
434253525051 is a wasteful number, since it uses less digits than its factorization.
434253525051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 264122.
The product of its (nonzero) digits is 360000, while the sum is 39.
Adding to 434253525051 its reverse (150525352434), we get a palindrome (584778877485).
The spelling of 434253525051 in words is "four hundred thirty-four billion, two hundred fifty-three million, five hundred twenty-five thousand, fifty-one".
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