Base | Representation |
---|---|
bin | 111111001100111100111… |
… | …011101101100000100001 |
3 | 120101012122110102202211221 |
4 | 333030330323231200201 |
5 | 1032124420430101423 |
6 | 13123130530335041 |
7 | 625534251521323 |
oct | 77147473554041 |
9 | 16335573382757 |
10 | 4343234222113 |
11 | 1424a56543946 |
12 | 5a18b842a481 |
13 | 256746a6b097 |
14 | 1102dc3c5613 |
15 | 77e9e05de5d |
hex | 3f33ceed821 |
4343234222113 has 2 divisors, whose sum is σ = 4343234222114. Its totient is φ = 4343234222112.
The previous prime is 4343234222087. The next prime is 4343234222177. The reversal of 4343234222113 is 3112224323434.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4211717749009 + 131516473104 = 2052247^2 + 362652^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4343234222113 is a prime.
It is not a weakly prime, because it can be changed into another prime (4343234222413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2171617111056 + 2171617111057.
It is an arithmetic number, because the mean of its divisors is an integer number (2171617111057).
Almost surely, 24343234222113 is an apocalyptic number.
It is an amenable number.
4343234222113 is a deficient number, since it is larger than the sum of its proper divisors (1).
4343234222113 is an equidigital number, since it uses as much as digits as its factorization.
4343234222113 is an evil number, because the sum of its binary digits is even.
The product of its digits is 82944, while the sum is 34.
Adding to 4343234222113 its reverse (3112224323434), we get a palindrome (7455458545547).
The spelling of 4343234222113 in words is "four trillion, three hundred forty-three billion, two hundred thirty-four million, two hundred twenty-two thousand, one hundred thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •