Base | Representation |
---|---|
bin | 110001011000001011001100… |
… | …1010100100100011111101011 |
3 | 2002221211122120221012022121222 |
4 | 1202300112121110210133223 |
5 | 423412040133332130121 |
6 | 4135424545442052255 |
7 | 160325250355015031 |
oct | 14260263124443753 |
9 | 2087748527168558 |
10 | 434331140114411 |
11 | 116433890672461 |
12 | 4086835004a08b |
13 | 15847334c33a17 |
14 | 7937a4caa2551 |
15 | 3532e3a3070ab |
hex | 18b05995247eb |
434331140114411 has 2 divisors, whose sum is σ = 434331140114412. Its totient is φ = 434331140114410.
The previous prime is 434331140114393. The next prime is 434331140114423. The reversal of 434331140114411 is 114411041133434.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 434331140114411 - 214 = 434331140098027 is a prime.
It is not a weakly prime, because it can be changed into another prime (434331140111411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 217165570057205 + 217165570057206.
It is an arithmetic number, because the mean of its divisors is an integer number (217165570057206).
Almost surely, 2434331140114411 is an apocalyptic number.
434331140114411 is a deficient number, since it is larger than the sum of its proper divisors (1).
434331140114411 is an equidigital number, since it uses as much as digits as its factorization.
434331140114411 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 27648, while the sum is 35.
Adding to 434331140114411 its reverse (114411041133434), we get a palindrome (548742181247845).
The spelling of 434331140114411 in words is "four hundred thirty-four trillion, three hundred thirty-one billion, one hundred forty million, one hundred fourteen thousand, four hundred eleven".
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