Base | Representation |
---|---|
bin | 10011110000010001100000… |
… | …11010001011100010101011 |
3 | 12200210211112001102221212201 |
4 | 21320020300122023202223 |
5 | 21143210322004314011 |
6 | 232220040042321031 |
7 | 12102305312351224 |
oct | 1170106032134253 |
9 | 180724461387781 |
10 | 43440111401131 |
11 | 1292893644a535 |
12 | 4a56b994b9177 |
13 | 1b315008c1283 |
14 | aa272686024b |
15 | 504e9c4e8cc1 |
hex | 27823068b8ab |
43440111401131 has 2 divisors, whose sum is σ = 43440111401132. Its totient is φ = 43440111401130.
The previous prime is 43440111401117. The next prime is 43440111401147. The reversal of 43440111401131 is 13110411104434.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 43440111401131 - 231 = 43437963917483 is a prime.
It is a super-2 number, since 2×434401114011312 (a number of 28 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 43440111401131.
It is not a weakly prime, because it can be changed into another prime (43440111401161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21720055700565 + 21720055700566.
It is an arithmetic number, because the mean of its divisors is an integer number (21720055700566).
Almost surely, 243440111401131 is an apocalyptic number.
43440111401131 is a deficient number, since it is larger than the sum of its proper divisors (1).
43440111401131 is an equidigital number, since it uses as much as digits as its factorization.
43440111401131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 28.
Adding to 43440111401131 its reverse (13110411104434), we get a palindrome (56550522505565).
The spelling of 43440111401131 in words is "forty-three trillion, four hundred forty billion, one hundred eleven million, four hundred one thousand, one hundred thirty-one".
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