Search a number
-
+
4350151302137 is a prime number
BaseRepresentation
bin111111010011011001001…
…110010001101111111001
3120101212111112010211210222
4333103121032101233321
51032233102213132022
613130233143345425
7626200542653354
oct77233116215771
916355445124728
104350151302137
111427986002503
125a3108a52275
132572a9b30844
14110796d1929b
1578256449242
hex3f4d9391bf9

4350151302137 has 2 divisors, whose sum is σ = 4350151302138. Its totient is φ = 4350151302136.

The previous prime is 4350151302097. The next prime is 4350151302163. The reversal of 4350151302137 is 7312031510534.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3846074021881 + 504077280256 = 1961141^2 + 709984^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4350151302137 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 4350151302097 and 4350151302106.

It is not a weakly prime, because it can be changed into another prime (4350151302337) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2175075651068 + 2175075651069.

It is an arithmetic number, because the mean of its divisors is an integer number (2175075651069).

Almost surely, 24350151302137 is an apocalyptic number.

It is an amenable number.

4350151302137 is a deficient number, since it is larger than the sum of its proper divisors (1).

4350151302137 is an equidigital number, since it uses as much as digits as its factorization.

4350151302137 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 37800, while the sum is 35.

The spelling of 4350151302137 in words is "four trillion, three hundred fifty billion, one hundred fifty-one million, three hundred two thousand, one hundred thirty-seven".