Base | Representation |
---|---|
bin | 111111010011011101100… |
… | …111100001100000011011 |
3 | 120101212200122212120020222 |
4 | 333103131213201200123 |
5 | 1032233230101413042 |
6 | 13130244335510255 |
7 | 626202426432044 |
oct | 77233547414033 |
9 | 16355618776228 |
10 | 4350225029147 |
11 | 1427a13689718 |
12 | 5a312968838b |
13 | 2572bc1a58aa |
14 | 1107a2a2b8cb |
15 | 7825cb5e2d2 |
hex | 3f4dd9e181b |
4350225029147 has 2 divisors, whose sum is σ = 4350225029148. Its totient is φ = 4350225029146.
The previous prime is 4350225029123. The next prime is 4350225029173. The reversal of 4350225029147 is 7419205220534.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4350225029147 - 216 = 4350224963611 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4350225029098 and 4350225029107.
It is not a weakly prime, because it can be changed into another prime (4350225029347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2175112514573 + 2175112514574.
It is an arithmetic number, because the mean of its divisors is an integer number (2175112514574).
Almost surely, 24350225029147 is an apocalyptic number.
4350225029147 is a deficient number, since it is larger than the sum of its proper divisors (1).
4350225029147 is an equidigital number, since it uses as much as digits as its factorization.
4350225029147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 604800, while the sum is 44.
The spelling of 4350225029147 in words is "four trillion, three hundred fifty billion, two hundred twenty-five million, twenty-nine thousand, one hundred forty-seven".
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