Base | Representation |
---|---|
bin | 111111010011011101100… |
… | …111100101011110111001 |
3 | 120101212200122220101121011 |
4 | 333103131213211132321 |
5 | 1032233230102423213 |
6 | 13130244340113521 |
7 | 626202426530401 |
oct | 77233547453671 |
9 | 16355618811534 |
10 | 4350225045433 |
11 | 1427a1369a983 |
12 | 5a31296958a1 |
13 | 2572bc1b0127 |
14 | 1107a2a33801 |
15 | 7825cb6403d |
hex | 3f4dd9e57b9 |
4350225045433 has 2 divisors, whose sum is σ = 4350225045434. Its totient is φ = 4350225045432.
The previous prime is 4350225045409. The next prime is 4350225045497. The reversal of 4350225045433 is 3345405220534.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3768983483769 + 581241561664 = 1941387^2 + 762392^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4350225045433 is a prime.
It is not a weakly prime, because it can be changed into another prime (4350225045833) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2175112522716 + 2175112522717.
It is an arithmetic number, because the mean of its divisors is an integer number (2175112522717).
Almost surely, 24350225045433 is an apocalyptic number.
It is an amenable number.
4350225045433 is a deficient number, since it is larger than the sum of its proper divisors (1).
4350225045433 is an equidigital number, since it uses as much as digits as its factorization.
4350225045433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 864000, while the sum is 40.
The spelling of 4350225045433 in words is "four trillion, three hundred fifty billion, two hundred twenty-five million, forty-five thousand, four hundred thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.142 sec. • engine limits •