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43540130054513 = 53821511887821
BaseRepresentation
bin10011110011001011110011…
…11111000100000101110001
312201011101200112011222202102
421321211321333010011301
521201330141243221023
6232334020513230145
712112446004026611
oct1171457177040561
9181141615158672
1043540130054513
11129672a1366154
124a72451562355
131b3aa80232201
14aa74d4178a41
155078a31ba628
hex279979fc4171

43540130054513 has 4 divisors (see below), whose sum is σ = 44361641942388. Its totient is φ = 42718618166640.

The previous prime is 43540130054471. The next prime is 43540130054539. The reversal of 43540130054513 is 31545003104534.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 26748632360464 + 16791497694049 = 5171908^2 + 4097743^2 .

It is a cyclic number.

It is not a de Polignac number, because 43540130054513 - 228 = 43539861619057 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (43540130059513) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 410755943858 + ... + 410755943963.

It is an arithmetic number, because the mean of its divisors is an integer number (11090410485597).

Almost surely, 243540130054513 is an apocalyptic number.

It is an amenable number.

43540130054513 is a deficient number, since it is larger than the sum of its proper divisors (821511887875).

43540130054513 is an equidigital number, since it uses as much as digits as its factorization.

43540130054513 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 821511887874.

The product of its (nonzero) digits is 216000, while the sum is 38.

The spelling of 43540130054513 in words is "forty-three trillion, five hundred forty billion, one hundred thirty million, fifty-four thousand, five hundred thirteen".

Divisors: 1 53 821511887821 43540130054513