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4354113 = 31451371
BaseRepresentation
bin10000100111000001000001
322012012201110
4100213001001
52103312423
6233153533
752003131
oct20470101
98165643
104354113
112504345
12155b8a9
13b95aca
14814ac1
155b0193
hex427041

4354113 has 4 divisors (see below), whose sum is σ = 5805488. Its totient is φ = 2902740.

The previous prime is 4354111. The next prime is 4354117. The reversal of 4354113 is 3114534.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 4354113 - 21 = 4354111 is a prime.

It is a D-number.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 4354113.

It is not an unprimeable number, because it can be changed into a prime (4354111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (7) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 725683 + ... + 725688.

It is an arithmetic number, because the mean of its divisors is an integer number (1451372).

Almost surely, 24354113 is an apocalyptic number.

It is an amenable number.

4354113 is a deficient number, since it is larger than the sum of its proper divisors (1451375).

4354113 is a wasteful number, since it uses less digits than its factorization.

4354113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1451374.

The product of its digits is 720, while the sum is 21.

The square root of 4354113 is about 2086.6511447772. The cubic root of 4354113 is about 163.2926230160.

Adding to 4354113 its reverse (3114534), we get a palindrome (7468647).

The spelling of 4354113 in words is "four million, three hundred fifty-four thousand, one hundred thirteen".

Divisors: 1 3 1451371 4354113