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43661050561147 is a prime number
BaseRepresentation
bin10011110110101101000010…
…11010001100001001111011
312201120221210200110011222011
421323112201122030021323
521210320312420424042
6232505335411310351
712124256351260045
oct1173264132141173
9181527720404864
1043661050561147
1112a03602889558
124a919795ab3b7
131b492b1042b56
14aad2c5858a95
1550aacdd9da17
hex27b5a168c27b

43661050561147 has 2 divisors, whose sum is σ = 43661050561148. Its totient is φ = 43661050561146.

The previous prime is 43661050561099. The next prime is 43661050561153. The reversal of 43661050561147 is 74116505016634.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-43661050561147 is a prime.

It is a super-2 number, since 2×436610505611472 (a number of 28 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 43661050561147.

It is not a weakly prime, because it can be changed into another prime (43661050561157) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21830525280573 + 21830525280574.

It is an arithmetic number, because the mean of its divisors is an integer number (21830525280574).

Almost surely, 243661050561147 is an apocalyptic number.

43661050561147 is a deficient number, since it is larger than the sum of its proper divisors (1).

43661050561147 is an equidigital number, since it uses as much as digits as its factorization.

43661050561147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1814400, while the sum is 49.

The spelling of 43661050561147 in words is "forty-three trillion, six hundred sixty-one billion, fifty million, five hundred sixty-one thousand, one hundred forty-seven".