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43815231113 is a prime number
BaseRepresentation
bin101000110011100101…
…110101111010001001
311012002120002100200112
4220303211311322021
51204213144343423
632043424244105
73110532214403
oct506345657211
9135076070615
1043815231113
1117644612705
1285a9770635
134193620574
142199185b73
151216910a78
hexa33975e89

43815231113 has 2 divisors, whose sum is σ = 43815231114. Its totient is φ = 43815231112.

The previous prime is 43815231059. The next prime is 43815231121. The reversal of 43815231113 is 31113251834.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 29442098569 + 14373132544 = 171587^2 + 119888^2 .

It is a cyclic number.

It is not a de Polignac number, because 43815231113 - 212 = 43815227017 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 43815231113.

It is not a weakly prime, because it can be changed into another prime (43815231193) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21907615556 + 21907615557.

It is an arithmetic number, because the mean of its divisors is an integer number (21907615557).

Almost surely, 243815231113 is an apocalyptic number.

It is an amenable number.

43815231113 is a deficient number, since it is larger than the sum of its proper divisors (1).

43815231113 is an equidigital number, since it uses as much as digits as its factorization.

43815231113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 8640, while the sum is 32.

Adding to 43815231113 its reverse (31113251834), we get a palindrome (74928482947).

The spelling of 43815231113 in words is "forty-three billion, eight hundred fifteen million, two hundred thirty-one thousand, one hundred thirteen".