Base | Representation |
---|---|
bin | 10100000000110111010000… |
… | …10010100101010100111101 |
3 | 12202211022211202221202001220 |
4 | 22000123220102211110331 |
5 | 21232030222304203123 |
6 | 233333550420223553 |
7 | 12161425046351163 |
oct | 1200335022452475 |
9 | 182738752852056 |
10 | 44010132100413 |
11 | 13028657257746 |
12 | 4b2956023abb9 |
13 | 1b731a355318b |
14 | ac215d327233 |
15 | 514c1047ace3 |
hex | 2806e84a553d |
44010132100413 has 32 divisors (see below), whose sum is σ = 62541855024000. Its totient is φ = 27450013556736.
The previous prime is 44010132100351. The next prime is 44010132100423. The reversal of 44010132100413 is 31400123101044.
It is not a de Polignac number, because 44010132100413 - 210 = 44010132099389 is a prime.
It is a super-2 number, since 2×440101321004132 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (44010132100423) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 13093438 + ... + 16107711.
It is an arithmetic number, because the mean of its divisors is an integer number (1954432969500).
Almost surely, 244010132100413 is an apocalyptic number.
It is an amenable number.
44010132100413 is a deficient number, since it is larger than the sum of its proper divisors (18531722923587).
44010132100413 is a wasteful number, since it uses less digits than its factorization.
44010132100413 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 29201501.
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 44010132100413 its reverse (31400123101044), we get a palindrome (75410255201457).
The spelling of 44010132100413 in words is "forty-four trillion, ten billion, one hundred thirty-two million, one hundred thousand, four hundred thirteen".
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