Base | Representation |
---|---|
bin | 100000000001011100001… |
… | …1000101110110001111001 |
3 | 120120202010000101011120001 |
4 | 1000002320120232301321 |
5 | 1034102013320030123 |
6 | 13205504504233001 |
7 | 632654231523634 |
oct | 100027030566171 |
9 | 16522100334501 |
10 | 4401140001913 |
11 | 1447570880306 |
12 | 5b0b78a6b761 |
13 | 25c044682105 |
14 | 113032a94c1b |
15 | 7973c9dc0ad |
hex | 400b862ec79 |
4401140001913 has 2 divisors, whose sum is σ = 4401140001914. Its totient is φ = 4401140001912.
The previous prime is 4401140001893. The next prime is 4401140001919. The reversal of 4401140001913 is 3191000411044.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2948902914169 + 1452237087744 = 1717237^2 + 1205088^2 .
It is a cyclic number.
It is not a de Polignac number, because 4401140001913 - 225 = 4401106447481 is a prime.
It is not a weakly prime, because it can be changed into another prime (4401140001919) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2200570000956 + 2200570000957.
It is an arithmetic number, because the mean of its divisors is an integer number (2200570000957).
Almost surely, 24401140001913 is an apocalyptic number.
It is an amenable number.
4401140001913 is a deficient number, since it is larger than the sum of its proper divisors (1).
4401140001913 is an equidigital number, since it uses as much as digits as its factorization.
4401140001913 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 28.
Adding to 4401140001913 its reverse (3191000411044), we get a palindrome (7592140412957).
The spelling of 4401140001913 in words is "four trillion, four hundred one billion, one hundred forty million, one thousand, nine hundred thirteen".
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