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4403143333049 is a prime number
BaseRepresentation
bin100000000010010111111…
…0010110101010010111001
3120120221021121222221020112
41000010233302311102321
51034120114143124144
613210435350434105
7633054665541326
oct100045762652271
916527247887215
104403143333049
1114483a969267a
125b1437962935
1325c2a3724756
14113182b79b4d
157980880b99e
hex4012fcb54b9

4403143333049 has 2 divisors, whose sum is σ = 4403143333050. Its totient is φ = 4403143333048.

The previous prime is 4403143332937. The next prime is 4403143333067. The reversal of 4403143333049 is 9403333413044.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4402728599824 + 414733225 = 2098268^2 + 20365^2 .

It is a cyclic number.

It is not a de Polignac number, because 4403143333049 - 212 = 4403143328953 is a prime.

It is a super-2 number, since 2×44031433330492 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 4403143332997 and 4403143333015.

It is not a weakly prime, because it can be changed into another prime (4403143333249) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2201571666524 + 2201571666525.

It is an arithmetic number, because the mean of its divisors is an integer number (2201571666525).

Almost surely, 24403143333049 is an apocalyptic number.

It is an amenable number.

4403143333049 is a deficient number, since it is larger than the sum of its proper divisors (1).

4403143333049 is an equidigital number, since it uses as much as digits as its factorization.

4403143333049 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 559872, while the sum is 41.

The spelling of 4403143333049 in words is "four trillion, four hundred three billion, one hundred forty-three million, three hundred thirty-three thousand, forty-nine".