Base | Representation |
---|---|
bin | 101001000000110001… |
… | …110011111000100001 |
3 | 11012122222101120121112 |
4 | 221000301303320201 |
5 | 1210141314103403 |
6 | 32121410233105 |
7 | 3116156560526 |
oct | 510061637041 |
9 | 135588346545 |
10 | 44036472353 |
11 | 17748493505 |
12 | 864b885795 |
13 | 41ca403c43 |
14 | 21ba6d714d |
15 | 122b0639d8 |
hex | a40c73e21 |
44036472353 has 2 divisors, whose sum is σ = 44036472354. Its totient is φ = 44036472352.
The previous prime is 44036472329. The next prime is 44036472367. The reversal of 44036472353 is 35327463044.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 26338693264 + 17697779089 = 162292^2 + 133033^2 .
It is a cyclic number.
It is not a de Polignac number, because 44036472353 - 212 = 44036468257 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 44036472353.
It is not a weakly prime, because it can be changed into another prime (44036412353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22018236176 + 22018236177.
It is an arithmetic number, because the mean of its divisors is an integer number (22018236177).
Almost surely, 244036472353 is an apocalyptic number.
It is an amenable number.
44036472353 is a deficient number, since it is larger than the sum of its proper divisors (1).
44036472353 is an equidigital number, since it uses as much as digits as its factorization.
44036472353 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 725760, while the sum is 41.
The spelling of 44036472353 in words is "forty-four billion, thirty-six million, four hundred seventy-two thousand, three hundred fifty-three".
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