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4405125413473 is a prime number
BaseRepresentation
bin100000000011010010111…
…1011110111101001100001
3120121010101202122001102121
41000012211323313221201
51034133144101212343
613211404153344241
7633155054130421
oct100064573675141
916533352561377
104405125413473
1114492264aaa74
125b18ab708081
1325c52b2665c5
141132d00cc481
15798c282eaed
hex401a5ef7a61

4405125413473 has 2 divisors, whose sum is σ = 4405125413474. Its totient is φ = 4405125413472.

The previous prime is 4405125413383. The next prime is 4405125413477. The reversal of 4405125413473 is 3743145215044.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4262870467584 + 142254945889 = 2064672^2 + 377167^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4405125413473 is a prime.

It is not a weakly prime, because it can be changed into another prime (4405125413477) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2202562706736 + 2202562706737.

It is an arithmetic number, because the mean of its divisors is an integer number (2202562706737).

Almost surely, 24405125413473 is an apocalyptic number.

It is an amenable number.

4405125413473 is a deficient number, since it is larger than the sum of its proper divisors (1).

4405125413473 is an equidigital number, since it uses as much as digits as its factorization.

4405125413473 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 806400, while the sum is 43.

The spelling of 4405125413473 in words is "four trillion, four hundred five billion, one hundred twenty-five million, four hundred thirteen thousand, four hundred seventy-three".