Base | Representation |
---|---|
bin | 100000000011010101010… |
… | …0100000010001001101001 |
3 | 120121010121011201110020202 |
4 | 1000012222210002021221 |
5 | 1034133323440113423 |
6 | 13211420005401545 |
7 | 633160016054264 |
oct | 100065244021151 |
9 | 16533534643222 |
10 | 4405203051113 |
11 | 1449266308307 |
12 | 5b19117092b5 |
13 | 25c54137a637 |
14 | 1132da53bcdb |
15 | 798c9568728 |
hex | 401aa902269 |
4405203051113 has 2 divisors, whose sum is σ = 4405203051114. Its totient is φ = 4405203051112.
The previous prime is 4405203051101. The next prime is 4405203051163. The reversal of 4405203051113 is 3111503025044.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4232269333504 + 172933717609 = 2057248^2 + 415853^2 .
It is a cyclic number.
It is not a de Polignac number, because 4405203051113 - 210 = 4405203050089 is a prime.
It is not a weakly prime, because it can be changed into another prime (4405203051163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2202601525556 + 2202601525557.
It is an arithmetic number, because the mean of its divisors is an integer number (2202601525557).
Almost surely, 24405203051113 is an apocalyptic number.
It is an amenable number.
4405203051113 is a deficient number, since it is larger than the sum of its proper divisors (1).
4405203051113 is an equidigital number, since it uses as much as digits as its factorization.
4405203051113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7200, while the sum is 29.
Adding to 4405203051113 its reverse (3111503025044), we get a palindrome (7516706076157).
The spelling of 4405203051113 in words is "four trillion, four hundred five billion, two hundred three million, fifty-one thousand, one hundred thirteen".
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