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4405232013513 = 31468410671171
BaseRepresentation
bin100000000011010110001…
…0010100001000011001001
3120121010200012012220012020
41000012230102201003021
51034133403343413023
613211422522235053
7633160520201622
oct100065422410311
916533605186166
104405232013513
11144928069a181
125b191b355a89
1325c54737b256
1411330031aa49
15798cbd89de3
hex401ac4a10c9

4405232013513 has 4 divisors (see below), whose sum is σ = 5873642684688. Its totient is φ = 2936821342340.

The previous prime is 4405232013473. The next prime is 4405232013577. The reversal of 4405232013513 is 3153102325044.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4405232013513 - 212 = 4405232009417 is a prime.

It is not an unprimeable number, because it can be changed into a prime (4405233013513) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 734205335583 + ... + 734205335588.

It is an arithmetic number, because the mean of its divisors is an integer number (1468410671172).

Almost surely, 24405232013513 is an apocalyptic number.

It is an amenable number.

4405232013513 is a deficient number, since it is larger than the sum of its proper divisors (1468410671175).

4405232013513 is a wasteful number, since it uses less digits than its factorization.

4405232013513 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1468410671174.

The product of its (nonzero) digits is 43200, while the sum is 33.

Adding to 4405232013513 its reverse (3153102325044), we get a palindrome (7558334338557).

The spelling of 4405232013513 in words is "four trillion, four hundred five billion, two hundred thirty-two million, thirteen thousand, five hundred thirteen".

Divisors: 1 3 1468410671171 4405232013513