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44113004314 = 222056502157
BaseRepresentation
bin101001000101010101…
…110000011100011010
311012212022101210201121
4221011111300130122
51210320412114224
632133142435454
73121106231011
oct510525603432
9135768353647
1044113004314
1117787706065
128671432b8a
13421021b922
1421c6939a78
151232b2ebe4
hexa4557071a

44113004314 has 4 divisors (see below), whose sum is σ = 66169506474. Its totient is φ = 22056502156.

The previous prime is 44113004293. The next prime is 44113004317. The reversal of 44113004314 is 41340031144.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 35444463289 + 8668541025 = 188267^2 + 93105^2 .

It is a super-3 number, since 3×441130043143 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not an unprimeable number, because it can be changed into a prime (44113004317) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11028251077 + ... + 11028251080.

Almost surely, 244113004314 is an apocalyptic number.

44113004314 is a deficient number, since it is larger than the sum of its proper divisors (22056502160).

44113004314 is a wasteful number, since it uses less digits than its factorization.

44113004314 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 22056502159.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 44113004314 its reverse (41340031144), we get a palindrome (85453035458).

The spelling of 44113004314 in words is "forty-four billion, one hundred thirteen million, four thousand, three hundred fourteen".

Divisors: 1 2 22056502157 44113004314