Base | Representation |
---|---|
bin | 1100110101101011001… |
… | …00110111010100001001 |
3 | 1120011122022120110211221 |
4 | 12122311210313110021 |
5 | 24211420022112131 |
6 | 534353111122041 |
7 | 43604454444412 |
oct | 6326544672411 |
9 | 1504568513757 |
10 | 441133004041 |
11 | 1600a1098114 |
12 | 715b2673321 |
13 | 327a23589a2 |
14 | 174cb020809 |
15 | b71cad5411 |
hex | 66b5937509 |
441133004041 has 2 divisors, whose sum is σ = 441133004042. Its totient is φ = 441133004040.
The previous prime is 441133004033. The next prime is 441133004047. The reversal of 441133004041 is 140400331144.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 300210847225 + 140922156816 = 547915^2 + 375396^2 .
It is a cyclic number.
It is not a de Polignac number, because 441133004041 - 23 = 441133004033 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 441133003997 and 441133004015.
It is not a weakly prime, because it can be changed into another prime (441133004047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 220566502020 + 220566502021.
It is an arithmetic number, because the mean of its divisors is an integer number (220566502021).
Almost surely, 2441133004041 is an apocalyptic number.
It is an amenable number.
441133004041 is a deficient number, since it is larger than the sum of its proper divisors (1).
441133004041 is an equidigital number, since it uses as much as digits as its factorization.
441133004041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 441133004041 its reverse (140400331144), we get a palindrome (581533335185).
The spelling of 441133004041 in words is "four hundred forty-one billion, one hundred thirty-three million, four thousand, forty-one".
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