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44114410131 = 31110912264223
BaseRepresentation
bin101001000101011011…
…000111101010010011
311012212102001020010220
4221011123013222103
51210321242111011
632133232524123
73121124204421
oct510533075223
9135772036126
1044114410131
11177884862a0
1286719b0643
1342105c177c
1421c6bc4111
151232d0b506
hexa456c7a93

44114410131 has 16 divisors (see below), whose sum is σ = 64755102720. Its totient is φ = 26490719520.

The previous prime is 44114410127. The next prime is 44114410169. The reversal of 44114410131 is 13101441144.

44114410131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 44114410131 - 22 = 44114410127 is a prime.

It is a super-2 number, since 2×441144101312 (a number of 22 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (44114410181) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6128515 + ... + 6135708.

It is an arithmetic number, because the mean of its divisors is an integer number (4047193920).

Almost surely, 244114410131 is an apocalyptic number.

44114410131 is a deficient number, since it is larger than the sum of its proper divisors (20640692589).

44114410131 is a wasteful number, since it uses less digits than its factorization.

44114410131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12264346.

The product of its (nonzero) digits is 768, while the sum is 24.

Adding to 44114410131 its reverse (13101441144), we get a palindrome (57215851275).

The spelling of 44114410131 in words is "forty-four billion, one hundred fourteen million, four hundred ten thousand, one hundred thirty-one".

Divisors: 1 3 11 33 109 327 1199 3597 12264223 36792669 134906453 404719359 1336800307 4010400921 14704803377 44114410131