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441351150135241 is a prime number
BaseRepresentation
bin110010001011010000001001…
…0100001100110011111001001
32010212200202110111112200020211
41210112200102201212133021
5430322044123413311431
64202401530323521121
7161651365636446343
oct14426402241463711
92125622414480224
10441351150135241
1111869aa762835a5
12416009872291a1
1315c36309035158
147adb71c66c293
1536058525a12b1
hex19168128667c9

441351150135241 has 2 divisors, whose sum is σ = 441351150135242. Its totient is φ = 441351150135240.

The previous prime is 441351150135167. The next prime is 441351150135361. The reversal of 441351150135241 is 142531051153144.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 399598500801600 + 41752649333641 = 19989960^2 + 6461629^2 .

It is a cyclic number.

It is not a de Polignac number, because 441351150135241 - 217 = 441351150004169 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 441351150135194 and 441351150135203.

It is not a weakly prime, because it can be changed into another prime (441351150133241) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 220675575067620 + 220675575067621.

It is an arithmetic number, because the mean of its divisors is an integer number (220675575067621).

Almost surely, 2441351150135241 is an apocalyptic number.

It is an amenable number.

441351150135241 is a deficient number, since it is larger than the sum of its proper divisors (1).

441351150135241 is an equidigital number, since it uses as much as digits as its factorization.

441351150135241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144000, while the sum is 40.

The spelling of 441351150135241 in words is "four hundred forty-one trillion, three hundred fifty-one billion, one hundred fifty million, one hundred thirty-five thousand, two hundred forty-one".