Base | Representation |
---|---|
bin | 1100110110001110111… |
… | …11111010111101000001 |
3 | 1120012102021101022120102 |
4 | 12123013133322331001 |
5 | 24213024011314423 |
6 | 534443012052145 |
7 | 43615065344462 |
oct | 6330737727501 |
9 | 1505367338512 |
10 | 441433698113 |
11 | 1602358a6011 |
12 | 71677304055 |
13 | 3281c73a685 |
14 | 17518d34d69 |
15 | b7391cec28 |
hex | 66c77faf41 |
441433698113 has 4 divisors (see below), whose sum is σ = 441484370628. Its totient is φ = 441383025600.
The previous prime is 441433698107. The next prime is 441433698131. The reversal of 441433698113 is 311896334144.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 287115932224 + 154317765889 = 535832^2 + 392833^2 .
It is a cyclic number.
It is not a de Polignac number, because 441433698113 - 26 = 441433698049 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (441433698313) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25323188 + ... + 25340613.
It is an arithmetic number, because the mean of its divisors is an integer number (110371092657).
Almost surely, 2441433698113 is an apocalyptic number.
It is an amenable number.
441433698113 is a deficient number, since it is larger than the sum of its proper divisors (50672515).
441433698113 is an equidigital number, since it uses as much as digits as its factorization.
441433698113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 50672514.
The product of its digits is 746496, while the sum is 47.
The spelling of 441433698113 in words is "four hundred forty-one billion, four hundred thirty-three million, six hundred ninety-eight thousand, one hundred thirteen".
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