Base | Representation |
---|---|
bin | 101001000111001111… |
… | …001100100100100111 |
3 | 11012221112022011122020 |
4 | 221013033030210213 |
5 | 1210402034321301 |
6 | 32140241034223 |
7 | 3121643640243 |
oct | 510717144447 |
9 | 135845264566 |
10 | 44144838951 |
11 | 177a3679984 |
12 | 8680025973 |
13 | 42169b69a5 |
14 | 21cac65423 |
15 | 123581c436 |
hex | a473cc927 |
44144838951 has 16 divisors (see below), whose sum is σ = 59423148288. Its totient is φ = 29149467200.
The previous prime is 44144838943. The next prime is 44144838973. The reversal of 44144838951 is 15983844144.
44144838951 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 44144838951 - 23 = 44144838943 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 44144838894 and 44144838903.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (44144838251) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 16005 + ... + 297566.
It is an arithmetic number, because the mean of its divisors is an integer number (3713946768).
Almost surely, 244144838951 is an apocalyptic number.
44144838951 is a deficient number, since it is larger than the sum of its proper divisors (15278309337).
44144838951 is a wasteful number, since it uses less digits than its factorization.
44144838951 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 314022.
The product of its digits is 2211840, while the sum is 51.
The spelling of 44144838951 in words is "forty-four billion, one hundred forty-four million, eight hundred thirty-eight thousand, nine hundred fifty-one".
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